|TAP 608- 2: The latent heat of fusion of ice
This experiment is designed to measure the amount of heat needed to turn 1 kg of ice at 0 oC into 1 kg of water at 0 oC
You will need
electric immersion heater (12 V, 60 W)
power supply (12 V ac, 6 A)
retort stand, boss and clamp
What to do
Set up the apparatus as shown in the diagram but without the ice. One heater should be connected to the power supply. The other is a control that is set up at the front of the lab. Do not switch on yet. Weigh your beakers. Crush the ice and put the same in each funnel trying to pack it closely round the heater.
Start the stopwatch and at the same time switch on the heater, adjusting the voltage to about
12 V. Record the voltage (V) and the current (I).
Leave the heater on for three minutes, adding more ice if needed to keep some in contact with the heater.
Switch off, remove the beaker and weigh it.
Observations and calculations
Mass of beaker = kg
Mass of beaker + melted ice = kg
Mass of melted ice = kg
Mass of control beaker = kg
Mass of control beaker + melted ice = kg
Mass of control melted ice = kg
Mass of ice melted due the heater alone = kg
Heater power (VI) = W
Time = s
Energy input = Power x Time = J
This energy melted __________ kg of ice.
So ____________J would melt 1 kg of ice.
This is the specific latent heat of fusion of ice.
The amount of heat needed to change 1 kg of solid to 1 kg of liquid at its melting point is called the specific latent heat of fusion of the material
This activity is taken from Resourceful Physics